The algorithm to print pattern using for loop in Python:
We need to use two for loops to print pattern, i.e. nested loops.There is a typical structure to print any pattern, i.e. the number of rows and column in the pattern. Outer loop tells us the number of rows used and inner loop tells us the column used to print pattern.
- Accept the number rows user want to print in the pattern.
- Iterate those number using outer for loop to handle the number of rows.
- Inner loop to handle the number of columns. Inner loop iteration depends on the values of the outer loop.
- Print start, number, asterisk, Pyramid and diamond pattern using the print() function.
- Add a new line after each row, i.e. after each iteration of outer for loop so you can display pattern appropriately.
Print Number pattern in Python
We created multiple examples which print different styles of number pattern. Let see them one by one.Example 1: – Print a number pattern using a for loop and range function. Let see the demo.
- # 10 is the total number to print
- for num in range(10):
- for i in range(num):
- print (num, end=" ") #print number
- # new line after each row to display pattern correctly
- print("\n")
- 1
- 2 2
- 3 3 3
- 4 4 4 4
- 5 5 5 5 5
- 6 6 6 6 6 6
- 7 7 7 7 7 7 7
- 8 8 8 8 8 8 8 8
- 9 9 9 9 9 9 9 9 9
- print("Second Number Pattern ")
- lastNumber = 6
- for row in range(1, lastNumber):
- for column in range(1, row + 1):
- print(column, end=' ')
- print("")
- Second Number Pattern
- 1
- 1 2
- 1 2 3
- 1 2 3 4
- 1 2 3 4 5
- print("Third Number Pattern")
- lastNumber = 6
- for row in range(1, lastNumber):
- for column in range(row, 0, -1):
- print(column, end=' ')
- print("")
- Third Number Pattern
- 1
- 2 1
- 3 2 1
- 4 3 2 1
- 5 4 3 2 1
- print("Fourth Number Pattern")
- lastNumber = 9
- for i in range(1, lastNumber):
- for j in range(-1+i, -1, -1):
- print(format(2**j, "4d"), end=' ')
- print("")
- Fourth Number Pattern
- 1
- 2 1
- 4 2 1
- 8 4 2 1
- 16 8 4 2 1
- 32 16 8 4 2 1
- 64 32 16 8 4 2 1
- 128 64 32 16 8 4 2 1
- print("Fifth Number Pattern")
- lastNumber = 9
- for i in range(1, lastNumber):
- for i in range(0, i, 1):
- print(format(2**i, "4d"), end=' ')
- for i in range(-1+i, -1, -1):
- print(format(2**i, "4d"), end=' ')
- print("")
- Fifth Number Pattern
- 1
- 1 2 1
- 1 2 4 2 1
- 1 2 4 8 4 2 1
- 1 2 4 8 16 8 4 2 1
- 1 2 4 8 16 32 16 8 4 2 1
- 1 2 4 8 16 32 64 32 16 8 4 2 1
- 1 2 4 8 16 32 64 128 64 32 16 8 4 2 1
- print("Sixth Number Pattern")
- currentNumber = 1
- stop = 2
- rows = 3 # Rows you want in your pattern
- for i in range(rows):
- for column in range(1, stop):
- print(currentNumber, end=' ')
- currentNumber += 1
- print("")
- stop += 2
- 1
- 2 3 4
- 5 6 7 8 9
- print("Number Pattern Example 7")
- start = 1
- stop = 2
- currentNumber = stop
- for row in range(2, 6):
- for col in range(start, stop):
- currentNumber -= 1
- print (currentNumber, end=' ')
- print("")
- start = stop
- stop +=row
- currentNumber = stop
- Number Pattern Example 7
- 1
- 3 2
- 6 5 4
- 10 9 8 7
Print Pyramid and Asterisk pattern in Python
Let’
see now how t print pyramid and asterisk(star) patterns in Python. Here
we will print the following pyramid pattern using an asterisk.
- Half pyramid Pattern
- Full pyramid Pattern
- Inverted pyramid Pattern
- Asterisk triangle pattern in python
- print("Print full Triangle pyramid using stars ")
- size = 7
- m = (2 * size) - 2
- for i in range(0, size):
- for j in range(0, m):
- print(end=" ")
- m = m - 1 # decrementing m after each loop
- for j in range(0, i + 1):
- # printing full Triangle pyramid using stars
- print("* ", end=' ')
- print(" ")
- Print full Triangle pyramid using stars
- *
- * *
- * * *
- * * * *
- * * * * *
- * * * * * *
- * * * * * * *
- print("Program to print half pyramid: ");
- rows = input("Enter number of rows ")
- rows = int (rows)
- for i in range (0, rows):
- for j in range(0, i + 1):
- print("*", end=' ')
- print("\r")
- Program to print half pyramid:
- Enter number of rows 4
- *
- * *
- * * *
- * * * *
- print("Program to print half pyramid: ")
- rows = input("Enter number of rows ")
- rows = int (rows)
- for i in range (rows,0,-1):
- for j in range(0, i + 1):
- print("*", end=' ')
- print("\r")
- Program to print half pyramid:
- Enter number of rows 5
- * * * * * *
- * * * * *
- * * * *
- * * *
- * *
- print("Program to print start pattern: \n");
- rows = input("Enter max star to be display on single line")
- rows = int (rows)
- for i in range (0, rows):
- for j in range(0, i + 1):
- print("*", end=' ')
- print("\r")
- for i in range (rows, 0, -1):
- for j in range(0, i -1):
- print("*", end=' ')
- print("\r")
- Program to print start pattern:
- Enter max star to be display on single line 4
- *
- * *
- * * *
- * * * *
- * * *
- * *
- *
- print("Program to print half pyramid: ")
- rows = input("Enter number of rows ")
- rows = int (rows)
- for i in range (rows,0,-1):
- for j in range(0, i + 1):
- print(j, end=' ')
- print("\r")
- Program to print half pyramid:
- Enter number of rows 5
- 0 1 2 3 4 5
- 0 1 2 3 4
- 0 1 2 3
- 0 1 2
- 0 1
Print Alphabets and Letters pattern in python
We are using an ASCII value of a letter, so we can convert ASCII value to a character to print it on screen. let’ see now how to print Alphabets and Letters patterns in Python with examples.- print("Print Alphabets and Letters pattern in python ")
- lastNumber = 6
- asciiNumber = 65
- for i in range(0, lastNumber):
- for j in range(0, i+1):
- character = chr(asciiNumber)
- print(character, end=' ')
- asciiNumber+=1
- print(" ")
- Print Alphabets and Letters pattern in python
- A
- B C
- D E F
- G H I J
- K L M N O
- P Q R S T U
Conclusion and Next Steps
Practice Problem: Print the following Pattern
- 0
- 2 4
- 4 8 8
- 8 16 16 16
- Solve our Python essential exercise for beginners to have a better understanding of Python basic concepts.
- Solve our Basic Python Quiz for beginners to test your fundamental Python skills.
1 2
1 2 3
1 2 3 4
1 2 3 4 5
print above pattern in python.
for j in range(1,i+1):
print(j,end=’ ‘)
print( )
I have updated the post with your question. Please check
———.|.———
——.|..|..|.——
—.|..|..|..|..|.—
——-WELCOME——-
—.|..|..|..|..|.—
——.|..|..|.——
———.|.———
for i in range(1,N,2):
print((i * “.|.”).center(M, “-“))
print(“WELCOME”.center(M,”-“))
for i in range(N-2,-1,-2):
print((i * “.|.”).center(M, “-“))
for I in range(1,n+1):
K=1
for j in range(1,n+1):
If i>=j:
Print(k,end=’ ‘)
Else:
Print(‘ ‘,end=’ ‘ )
Print()
for row in range(1, num):
for column in range(1, row + 1):
print(column, end=’ ‘)
print(“”)
def first(n):
for i in range(0, n):
for j in range(0, i+1):
print(j+1,end=”)
print(“\r”)
inp = input(‘Enter The Numbers Of Rows ‘)
inp = int(inp)
first(inp)
for i in range(1 , lastNumber):
for j in range(1 , i+1):
print(j , end=””)
print(” “)
lastNumber = 6
for row in range(1, lastNumber):
for column in range(1, row + 1):
print(column, end=’ ‘)
print(“”)
for j in range(1,i+1):
print(j,end=””)
print()
for i in range(1,n+1):
for j in range(1,i+1):
print(j ,end=’ ‘)
print()
n=int(input(“How many row you want to enter?”))
pattern(n)
2 6
3 7 10
4 8 11 13
5 9 12 14 15
I want this pattern in python
for i in range(num):
val=i+1
for j in range(i+1):
print(format(val, “<4"), end="")
val=val+((num-1)-j)
print()
enter no. of rows : 5
1
2 6
3 7 10
4 8 11 13
5 9 12 14 15
2 6
3 7 10
4 8 11 13
5 9 12 14 15”);
K=i
M=4
For j in range(i):
Print(k,end=’ ‘)
K=K+M
M=M-1
Print ()
2 2
4 4 4
8 8 8 8
how do we make this one?
z=0
for x in range(0,n):
for y in range(0,x+1):
print(z,end=”)
z=2**(x+1)
print()
Please help me with this.
n=0
for i in range(1,e+1):
for j in range(0,i):
print(n,end=” “)
n=2**i
print()
Enter the number:4
0
2 2
4 4 4
8 8 8 8
**
***
****
*****
******
*****
****
***
**
*
How do we make this one?
AAAA****AAAA
BBB***BBB
CC**CC
D*D
for j in range(4-i):
print(chr(65+i),end=”)
for j in range(4-i):
print(“*”,end=”)
for j in range(4-i):
print(chr(65+i),end=”)
print(‘\n’,end=”)
char = [” “,”D”,”C”,”B”,”A”]
while counter !=0:
out1 = char[counter] * counter
out2 = “*” * counter
print(out1 + out2 + out1)
counter -=1
for i in range(0,n):
print(chr(65+i)*(n-i), end=””)
print(“*”*(n-i), end=””)
print(chr(65+i)*(n-i), end=””)
print()
AAAA****AAAA
BBB***BBB
CC**CC
D*D
counter = 1
out = 0
print(“Pattern1”)
while counter < 6:
out = counter * star
print(out)
counter +=1
counter = 5
while counter !=0:
out = counter * star
print(out)
counter -=1
———.|.———
——.|..|.|..|.——
—.|..|..|..|..|.—
——-WELCOME——-
—.|..|..|..|..|.—
——.|..|.|..|.——
———.|.———
for i in range(1,n+1):
s= ‘*’*i
print(s)
for j in range(n+1,1,-1):
y = ‘*’ * j
print(y)
i=1
while i<=n :
print("*"*i)
i+=1
j=1
while j<=n :
print("*"*(n-j))
j+=1
enter a num6
*
**
***
****
*****
******
*****
****
***
**
*
*
**
***
****
*****
******
*****
****
***
**
*
while num<=0:
print('Error! Enter a positive number: ')
num=int(input('Enter a number: '))
for row in range (num):
for col in range (row):
print('*', end='')
print()
for i in range (num,0,-1):
for j in range (i):
print('*', end='')
print()
1
12
123
12
1
for i in range(1,n):
for j in range(1,i+1):
print(j,end=””)
print()
for i in range(n,0,-1):
for j in range(1,i+1):
print(j,end=””)
print()
enter a num3
1
12
123
12
1
i=1
while i<=n :
print("* "*i)
i+=1
j=1
while j<=n :
print("* "*(n-j))
j+=1
*
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *
* * * * * *
* * * * *
* * * *
* * *
* *
*
how do I make an hourglass shape with stars
*******
*****
***
*
***
*****
*******
*********
e1 = 7
s2 = 0
e2 = 0
for x in range(4):
for y in range(s2,e2):
print(” “,end=””)
for z in range(s1,e1):
print(“*”,end=””)
print()
s1 += 1
e1 -= 1
e2 += 1
s1 -= 1
e1 += 1
e2 -= 1
for x in range(3):
s1 -= 1
e1 += 1
e2 -= 1
for y in range(s2,e2):
print(” “,end=””)
for z in range(s1,e1):
print(“*”,end=””)
print()
if i % 2 !=0:
print(i * “*”)
for i in range(2,10):
if i % 2 !=0:
print(i * “*”)
def first(n):
for i in range(0, n):
for j in range(i,n ):
print(‘* ‘,end=”)
print(“\r”)
for i in range(0, n):
for j in range(0, i+1):
print(‘* ‘,end=”)
print(“\r”)
inp = input(‘Enter The Numbers Of Rows ‘)
inp = int(inp)
first(inp)
for i in range(n,0,-1):
print(“*”*i)
for j in range(1,n+1):
print(“*”*j)
enter a number : 9
*********
********
*******
******
*****
****
***
**
*
*
**
***
****
*****
******
*******
********
*********
for i in range(n,0,-1):
print(“*”*i)
for j in range(1,n+1):
print(“*”*j)
enter number : 9
*********
********
*******
******
*****
****
***
**
*
*
**
***
****
*****
******
*******
********
*********
n=int(input(“enter a number : “))
for i in range(n,0,-2):
print(“*”*i)
for j in range(2,n+1,2):
print(“*”*j)
*********
*******
*****
***
*
**
****
******
********
1
2 3 4
5 6 7 8 9
n=1
for i in range(1,x*2,2):
for j in range(0,i):
print(n,””,end=””)
n=n+1
print()
enter no. of rows3
1
2 3 4
5 6 7 8 9
1
3 2
4 5 6
10 9 8 7
1 2 3 4 5 6
2 3 4 5 6
3 4 5 6
4 5 6
5 6
6
for i in range (1, last_num):
for j in range(i, last_num, +1):
print( j, end= ” “)
print()
Sorry for wrong typing
3 5 7 9
5 7 9
7 9
9
slove this
for i in range(1,n+1,2):
for j in range(i,n+1,2):
print(j,end=” “)
print()
enter no.9
1 3 5 7 9
3 5 7 9
5 7 9
7 9
9
for j in range(i,7):
print(j,end=””)
print()
123456
23456
3456
456
56
6
0
101
21012
3210123
432101234
54321012345
for i in range(0,n+1):
for j in range(i,0,-1):
print(j,end=””)
print(0,end=””)
for k in range(1,i+1):
print(k,end=””)
print()
enter no.5
0
101
21012
3210123
432101234
54321012345
*2*
*232*
*2*
*
####
####
####
####
print(“####”)
**
***
**
*
some help on this?
i=1
while i<=n :
print("*"*i)
i+=1
j=1
while j<=n :
print("*"*(n-j))
j+=1
enter a num3
*
**
***
**
*
4 3 2 1 0 1 2 3 4
3 2 1 0 1 2 3
2 1 0 1 2
1 0 1
0
How to get this pattern?
0
1 0 1
2 1 0 1 2
3 2 1 0 1 2 3
4 3 2 1 0 1 2 3 4
I tired and think every stuff but I dont understand what i am missing. I am having a issue with generating 101, 21012, 3210123, 43211234
here is my code(which is wrong)
for i in range (1,6):
for t in range (i,5):
print(‘\t’, end=””)
for j in range (0,(2*i-1)):
print(2*i-1-j, “\t”, end=””)
print(“”)
*
* *
* * *
4 4 4 4
4 3 3 3
4 3 2 2
4 3 2 1
while counter < 4:
print(counter * "*")
counter +=1
2 2 2
3 3 3 3 3
4 4 4 4 4 4 4
how do we make this one?
count=1
for row in range(1,n+1):
for col in range(1,row+count):
print(row,end=””)
count=count+1
print()
1 2 3
4 5 6
7 8 9
print(“4 5 6”)
print(“7 8 9”)
*
*
*
*
* * * *
*
* * * *
*
*
Just like this but if we have any words like input
ABCDEF FEDCBA
ABCDE EDCBA
ABCD DCBA
ABC CBA
AB BA
A A
1 2 4 7
3 5 8 11
6 9 12 14
10 13 15 16
How do you write this function using recursion?
print(“Program to print start pattern: \n”);
rows = input(“Enter max star to be display on single line”)
rows = int (rows)
for i in range (0, rows):
for j in range(0, i + 1):
print(“*”, end=’ ‘)
print(“\r”)
for i in range (rows, 0, -1):
for j in range(0, i -1):
print(“*”, end=’ ‘)
print(“\r”)
Thank you,
Mary
* * *
* *
*
how will we do this??
***
**
*
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Help its urgent
# * # * # * # * #
* # * # * # * #
# * # * # *
* # * # *
# * #
* #
#
Need help with this.
@@@ @@@
@@@***@
@@@ @@@
n=5
@@@@@ @@@@
@@@@@ @
@@@@@*****@
@@@@@ @
@@@@@ @@@@@
print above pattern in python
1. why we are using end = ‘ ‘? wht is the purpose of it.
2. need explanation for 3rd argument in range() ex- rage(1, 11, -1)
end = ‘ ‘
used to have space between numbers or stars.For example, if we executing loop 5 times and in each iteration we are printing
print("*", end=', ')
this statemment. this will print*,*,*,*,*
For second question
range(11, 1, -1)
this will print range in reverse order. i.e.11, 10, 9....0
For better understanding on range function please refer to Python range() function10
101
1010
10101
14 12 9 6
11 8 5 3
7 4 2 1
Pattern for this!!!
10
101
1010
10101
232
34543
4567654
567898765
67890109876
7890123210987
890123454321098
90123456765432109
0123456789876543210
**
***
****
*****
****
***
**
*
**
***
****
*****
****
***
**
*
A
B B
C C C
D D D D
E E E E E
F F F F F F
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
THIRD
*
* *
* * *
* * * *
* * * * *
* * * * * *
* * * * * * *
* * * * * * * *
* * * * * * * * *
Here is the basis code to use:
for i in range(3):
for j in range(3-i):
print(“*”, end=” “)
print(“”)
–******
—*****
—-****
—–***
——**
——-+
plz kindly tell me how to make this?
*
***
*****
*******
*********
for i in range(n):
for j in range(i+1):
print(“*”,end=””)
print()
for i in range(1,n+1):
for j in range(1):
print((2*i-1)*”*”,end=””)
print()
01000
00100
00010
00001
create the following pattern
for i in range(n):
for j in range(n):
if j==i:
print(“1″,end=””)
else:
print(“0″,end=””)
print()
Input number : 3
Expected Output :
*
* *
* *
for j in range(1):
if i==1:
print(i*”*”,end=””)
else:
print(2*”*”,end=””)
print()
2 3 4 5 6 7 8
3 4 5 6 7
4 5 6
5
what is the code for this pattern in python
**2 3 4 5 6 7 8
****3 4 5 6 7
******4 5 6
********5
what is the code for this pattern in python
******O***
******O***
*O********
*****O****
How do make this 5 * 10 grid by using random function and each row have only one ‘O’ and the position are random?
1
2 2
3 3 3
4 4 4 4
*****
*
*
*
*
*****
2 2
3 3 3
4 4 4 4
program for this ?
for j in range (1,6):
if j<=i:
print(i,end='')
print()
for i in range (1,n+1):
for j in range(1,i+1):
print(i,end=” “)
print( )
* * * *
* * *
* *
*
pls help some bady
*
* *
* * *
* * * *
* * * * *
* *
* * *
* * * *
* * * * *
* * * * *
* * * *
* * *
* *
*
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Plese Solve this number pattern 9in Python
1 2 1
1 2 3 2 1
1 2 1
1
please help me to write “”bottom part of this diamond of numbers””
12 21
123 321
1234 4321
1234554321
how to print this?
take your code editor and ask someone to do this for you and take the credit.
after writing the code press run or f5 then itll be printed.
22345
33345
44445
55555
how do i print this one?
2 2 3 4 5
3 3 3 4 5
4 4 4 4 5
5 5 5 5 5
how do i print this one?